2012-03-09

SICP Exercise 2.85: Simplifying Types

This section mentioned a method for "simplifying" a data object by lowering it in the tower of types as far as possible. Design a procedure drop that accomplishes this for the tower described in exercise 2.83. The key is to decide, in some general way, whether an object can be lowered. For example, the complex number 1.5 + 0i can be lowered as far as real, the complex number 1 + 0i can be lowered as far as integer, and the complex number 2 + 3i cannot be lowered at all. Here is a plan for determining whether an object can be lowered: Begin by defining a generic operation project that "pushes" an object down in the tower. For example, projecting a complex number would involve throwing away the imaginary part. Then a number can be dropped if, when we project it and raise the result back to the type we started with, we end up with something equal to what we started with. Show how to implement this idea in detail, by writing a drop procedure that drops an object as far as possible. You will need to design the various projection operations and install project as a generic operation in the system. You will also need to make use of a generic equality predicate, such as described in exercise 2.79. Finally, use drop to rewrite apply-generic from exercise 2.84 so that it "simplifies" its answers.

The procedure project is very similar in function to raise, except that it pushes objects down the tower of types instead of pulling them up. If we had coercion procedures installed for each type that could coerce an object to the next lowest type in the tower, rounding or discarding components as necessary to force the coercion, then the implementation of project can be based upon raise.

I'm all for repeating patterns that are known to work, so let's give ourselves such coercion procedures. Here's what we want them to do:
  • rational->integer needs to compute the nearest integer value that corresponds to the rational number representation. We can achieve this by calculating the result of dividing the numerator by the denominator and then using round to round this appropriately.
  • real->rational needs to calculate the nearest rational representation of the real number. Now we're using Scheme's internal real number representation, so we can use a few built-in Scheme procedures to help us... Given a Scheme real number, numerator and denominator will calculate the nearest rational representation for that number and then return their numerator and denominator respectively. However, it will return these as Scheme real numbers, so we need to convert them to Scheme integers before we can make our rational number. The built-in procedure inexact->exact can do this for us. Note that round will not - given a Scheme real number it will round it to the nearest integer value, but will continue to represent it as a Scheme real number, which would fall foul of our integer? checks in make-rational.
  • complex->real simply throws away the imaginary part of the complex number.
Here are the corresponding updates to the packages:
(define (install-rational-package)
  ;; internal procedures
  …
  (define (rational->integer r) (make-integer (round (/ (numer r) (denom r)))))
  …
  ;; interface to rest of the system
  …
  (put-coercion 'rational 'integer rational->integer)
  …
  'done)

(define (install-real-package)
  …
  (define (real->rational r) (make-rational (inexact->exact (numerator r))
                                            (inexact->exact (denominator r))))
  …
  (put-coercion 'real 'rational real->rational)
  …
  'done)

(define (install-complex-package)
  ;; imported procedures from rectangular and polar packages
  …
  ;; internal procedures
  …
  (define (complex->real z) (make-real (complex-real-part z)))
  …
  ;; interface to rest of the system
  …
  (put-coercion 'complex 'real complex->real)
  …
  'done)
Okay, so now let's produce project. Our existing raise procedure simply walks through the tower-of-types until it finds a match, finds the coercion procedure that corresponds to that type and the following type in the tower-of-types, and uses that to perform the raise. We should be able to do something similar. There are at least a couple of ways we could achieve this:
  • We could pull out apply-raise from our implementation of raise, and then simply have project invoke this with the reverse of the tower-of-types. This would walk through the tower-of-types from highest to lowest type and so would find and apply the coercion procedure corresponding to the type and its next lowest type.
  • Alternatively we could simply walk through the tower-of-types in order, as per raise, but check the second element in the remaining types at each iteration to see if it matches the type of our argument. If it does then we know that the next lowest type is the first element in the remaining types and so can find and apply the coercion procedure using these types. This version requires slightly different error checking from the original raise, but is pretty straightforward to implement.
It doesn't really matter which we use, so here's both...

First, here's the solution using reverse, including the changes to raise:
(define (apply-raise x types)
  (cond ((null? types)
         (error "Type not found in the tower-of-types"
                (list (type-tag x) tower-of-types)))
        ((eq? (type-tag x) (car types))
         (if (null? (cdr types))
             x
             (let ((raiser (get-coercion (type-tag x) (cadr types))))
               (if raiser
                   (raiser (contents x))
                   (error "No coercion procedure found for types"
                          (list (type-tag x) (cadr types)))))))
        (else (apply-raise x (cdr types)))))

(define (raise x)
  (apply-raise x tower-of-types))

(define (project x)
  (apply-raise x (reverse tower-of-types)))
...and here's the solution using an independent implementation of project:
(define (project x)
  (define (apply-project types)
    (cond ((eq? (type-tag x) (car types)) x)
          ((or (null? types) (null? (cdr types)))
           (error "type not found in the tower-of-types"
                  (list (type-tag x) tower-of-types)))
          ((eq? (type-tag x) (cadr types))
           (let ((projector (get-coercion (type-tag x) (car types))))
             (if projector
                 (projector (contents x))
                 (error "No coercion procedure found for types"
                        (list (car types) (type-tag x))))))
          (else (apply-project (cdr types)))))
  (apply-project tower-of-types))
They both produce the same results - I've verified this... Here's the results of one of my sets of tests:
> (project (make-real 3.5))
(rational 7 . 2)
> (project (make-rational 7 3))
(integer . 2)
> (raise (project (make-real 3.5)))
(real . 7/2)
> (raise (project (make-rational 7 3)))
(rational 2 . 1)
Now we can move on to drop itself.

This is fairly straightforward and can be achieved recursively by projecting the value passed to it, raiseing the result of this, and then determining whether or not we managed to project it to a lower level successfully. If we did then we can recurse on the projected value; if not then we should return the value unchanged.

Note that testing "whether or not we managed to project it to a lower level successfully" requires two tests:
  • We need to check that the result of raiseing the result of projecting the value is equal to the value we started with.
  • We also need to remember that project will return the value itself if we are at the bottom of the hierarchy, and so we need to check that the projected value has a different type from the original value. If we don't test this then an infinite loop will result. Why? Well, consider what would happen if we tried to drop an integer in the manner described above, but without testing that project actually changed the type (and before we've made any further changes to apply-generic):
    1. First we would project the value, which would give us back the same integer value.
    2. We would then raise the result of the project, which would give us an equivalent rational value.
    3. We would then check for equality between the integer value and its equivalent raiseed rational using equ?.
    4. This would invoke apply-generic for the operator 'equ?.
    5. This would raise the integer value to a rational and then get and apply the equ? procedure from the rational package, which would return true.
    6. We would now consider the drop to be successful, and so would recurse again. And again. And again...
Anyway, here's drop in all it's glory:
(define (drop x)
  (let* ((dropped (project x))
         (raised (raise dropped)))
    (if (and (not (eq? (type-tag x) (type-tag dropped)))
             (equ? x raised))
        (drop dropped)
        x)))
Let's put it to the test:
> (drop (make-integer 5))
(integer . 5)
> (drop (make-complex-from-real-imag 42 0))
(integer . 42)
> (drop (make-complex-from-real-imag 3/4 0))
(rational 3 . 4)
> (drop (make-real 2.5))
(rational 5 . 2)
Okay, so last step now... Updating apply-generic so it simplifies its answers. The simple way of achieving this is to turn the current apply-generic into an inner procedure, call this, and then drop the result. Of course, we should note that not all installed procedures return a tagged value. After all, we're using equ? as part of drop. So we should only apply drop to the result if we've got a tagged type. We can test that by checking to see if the result is a pair? whose car is in the tower-of-types.

Here's the updated apply-generic:
(define (apply-generic op . args)
  (define (find-and-apply-op)
    (let* ((type-tags (map type-tag args))
           (proc (get op type-tags)))
      (if proc
          (apply proc (map contents args))
          (if (> (length args) 1)
              (let* ((highest-type (find-highest-type type-tags))
                     (mapped-args (raise-all-to highest-type args))
                     (mapped-types (map type-tag mapped-args))
                     (mapped-proc (get op mapped-types)))
                (if mapped-proc
                    (apply mapped-proc (map contents mapped-args))
                    (error
                     "No method for these types -- APPLY-GENERIC"
                     (list op type-tags))))))))
  (let ((result (find-and-apply-op)))
    (if (and (pair? result)
             (memq (type-tag result) tower-of-types))
        (drop result)
        result)))
Let's test it... We'll use addd again, along with other operations:
> (addd (make-rational 1 3) (make-rational 2 3) (make-rational 2 2))
(integer . 2)
> (addd (make-real 3.5) (make-rational 3 2) (make-complex-from-real-imag 5 0))
(integer . 10)
> (add (make-real 4.25) (make-rational 5 2))
(rational 27 . 4)
> (sub (make-complex-from-real-imag 5 2) (make-complex-from-real-imag 2 2))
(integer . 3)

2012-03-07

SICP Exercise 2.84: Successive Raising

Using the raise operation of exercise 2.83, modify the apply-generic procedure so that it coerces its arguments to have the same type by the method of successive raising, as discussed in this section. You will need to devise a way to test which of two types is higher in the tower. Do this in a manner that is "compatible" with the rest of the system and will not lead to problems in adding new levels to the tower.

Let's start with producing "a way to test which of two types is higher in the tower."

In the previous exercise we created an ordered list, tower-of-types, which describes the tower of types we're using. We used this in the implementation of the raise operation to determine the next highest type for the value that was being raised so that we could then retrieve the appropriate coercion procedure and apply it.

We can utilize the tower-of-types here too. We've already generalized apply-generic so that it can cope with variable arguments. So rather than just testing "which of two types is higher in the tower," let's just generalize our test procedure straightaway to cope with variable arguments.

We already know that we can get the types of a list of values by evaluating (map type-tag values). Given such a list of the value's types we can then find the highest type by following these steps:
  1. Go through the tower-of-types, in order, from lowest to highest.
  2. With each type from the tower, filter out that type from the list of the values' types.
  3. If we get to the point where the filtered list of the values' types is empty then the highest type will be the last type that was filtered out from the list.
There are a couple of error cases, of course:
  • If the list of the values' types is empty to begin with then there isn't a highest type - there aren't any types! We'll return #f in this case to show that we successfully determined that there is no highest type.
  • If we've filtered out the top type from the tower-of-types and the filtered list of the values' types is still not empty then there must be values with types that aren't in the tower-of-types. This is a programming error and so we'll report it as such.
Here's the code:
(define (find-highest-type l)
  (define (filter-type t f)
    (cond ((null? f) '())
          ((eq? (car f) t) (filter-type t (cdr f)))
          (else (cons (car f) (filter-type t (cdr f))))))
  (define (find-highest highest remaining-tower remaining-list)
    (cond ((null? remaining-list) highest)
          ((null? remaining-tower)
           (error "Cannot find highest type from non-tower types -- FIND-HIGHEST-TYPE"
                  remaining-list))
          (else (find-highest (car remaining-tower)
                              (cdr remaining-tower)
                              (filter-type (car remaining-tower) remaining-list)))))
  (find-highest #f tower-of-types l))
...and here it is in action:
> (find-highest-type '(integer real rational real))
real
> (find-highest-type '(rational rational rational))
rational
> (find-highest-type '(complex real rational integer))
complex
> (find-highest-type '())
#f
> (find-highest-type '(integer wibble real wobble complex))
Cannot find highest type from non-tower types -- FIND-HIGHEST-TYPE (wibble wobble)
Assuming we have this wrapped up in a procedure that finds the highest type for a list of arguments, we'll also need a way of applying "the method of successive raising". This is a straightforward recursive procedure that takes a value to be raised and a type to raise it to and keeps raising the value using raise until it is of the requested type. For safety's sake let's also make sure that the type we're raising to is actually a valid type.

Here's the procedure:
(define (raise-to type value)
  (cond ((eq? type (type-tag value)) value)
        ((memq type tower-of-types) (raise-to type (raise value)))
        (else (error "Cannot raise to non-tower type -- RAISE-TO"
                     (list type tower-of-types)))))
Let's see this in action too:
> (raise-to 'real (make-integer 4))
(real . 4)
> (raise-to 'complex (make-rational 3 4))
(complex rectangular 3/4 . 0)
> (raise-to 'real (make-real 3.14159))
(real . 3.14159)
> (raise-to 'wibble (make-integer 42))
Cannot raise to non-tower type -- RAISE-TO (wibble (integer rational real complex))
We can then wrap this in another procedure that will take a type and a list of values and raises all of the values to that type:
(define (raise-all-to type values)
  (if (null? values)
      '()
      (cons (raise-to type (car values)) (raise-all-to type (cdr values)))))
This works like this:
> (raise-all-to 'real (list (make-integer 42) (make-real 3.14159) (make-rational 3 4)))
((real . 42) (real . 3.14159) (real . 3/4))
> (raise-all-to 'complex '())
()
> (raise-all-to 'wibble (list (make-integer 123)))
Cannot raise to non-tower type -- RAISE-TO (wibble (integer rational real complex))
Given all the above, updating apply-generic is straightforward. As before we start by trying to find and apply a procedure that corresponds directly to the raw arguments. Then, if no appropriate procedure can be found, and there are at least two arguments, we simply find the highest type from the arguments' types, raise all of the arguments to this type, get the procedure that corresponds to arguments of this type and then apply it.

To make the code cleaner we'll use let* again:
(define (apply-generic op . args)
  (let* ((type-tags (map type-tag args))
         (proc (get op type-tags)))
    (if proc
        (apply proc (map contents args))
        (if (> (length args) 1)
            (let* ((highest-type (find-highest-type type-tags))
                   (mapped-args (raise-all-to highest-type args))
                   (mapped-types (map type-tag mapped-args))
                   (mapped-proc (get op mapped-types)))
              (if mapped-proc
                  (apply mapped-proc (map contents mapped-args))
                  (error
                   "No method for these types -- APPLY-GENERIC"
                   (list op type-tags))))))))
To test this out let's use the addd procedure we introduced in exercise 2.82. In that exercise we only defined it for the complex package, so let's first add implementations to the other packages:
(define (install-integer-package)
  …
  (put 'addd '(integer integer integer)
       (lambda (x y z) (tag (+ x y z))))
  …
  'done)

(define (install-rational-package)
  ;; internal procedures
  …
  (define (addd x y z) 
       (make-rat (+ (* (numer x) (denom y) (denom z))
                    (* (denom x) (numer y) (denom z))
                    (* (denom x) (denom y) (numer z)))
                 (* (denom x) (denom y) (denom z))))
  …
  ;; interface to rest of the system
  …
  (put 'addd '(rational rational rational)
       (lambda (x y z) (tag (addd x y z))))
  …
  'done)

(define (install-real-package)
  …
  (put 'addd '(real real real)
       (lambda (x y z) (tag (+ x y z))))
  …
  'done)
...and, finally, let's give it a spin:
> (addd (make-real 3.14159) (make-rational 3 4) (make-complex-from-real-imag 1 7))
(complex rectangular 4.89159 . 7)
> (addd (make-rational 1 2) (make-rational 1 4) (make-rational 1 8))
(rational 7 . 8)
> (addd (make-integer 42) (make-real 3.14159) (make-rational 2 5))
(real . 45.54159)

2012-03-04

SICP Exercise 2.83: Raising Types

Suppose you are designing a generic arithmetic system for dealing with the tower of types shown in figure 2.25: integer, rational, real, complex. For each type (except complex), design a procedure that raises objects of that type one level in the tower. Show how to install a generic raise operation that will work for each type (except complex).

New Types and Type Checking

Before we start into raising types, we should note that the system we've been developing in sections 2.5.1 and 2.5.2 does not deal with the tower of types presented in figure 2.25. At the moment our system has the following tower of types:
      complex
         ↑
      rational
         ↑
   scheme-number
One way of dealing with this is to note that Scheme itself has its own tower of types which matches the tower of types we need for this exercise and that the scheme-number package will work with any type of Scheme number, not just integers. As a result we can use scheme-number as the basis for any of the types required for this exercise by copying the scheme-number package, and then changing the name of the package and the type tag in use in the copy. To keep us on our toes we'll only represent the integer and real types in this manner, and leave the rational and complex types as they are.

Of course the scheme-number package doesn't restrict what type of Scheme number it can represent. So that in itself leaves our system open to abuse - if we were to create the integer package using just the steps above (i.e. without further changes) there would be nothing to stop an (ab)user of the system from using the integer package to make an "integer" using a rational, real or complex Scheme number as the "integer" value to be represented.

In order to prevent such abuse, and to ensure that our system is well behaved, we'll need to make sure that the integer package is only ever used to represent integers, while the real package is only ever used to represent real numbers. Thankfully Scheme provides the integer? and real? predicates (and the corresponding rational? and complex? predicates too) which perform the appropriate tests. We can use these to modify the procedures installed for 'make in the two packages so that they enforce the correct type.

This gives us the following implementations for these packages:
;;;
;;; Integer package
;;;
(define (install-integer-package)
  (define (tag x)
    (attach-tag 'integer x))    
  (put 'add '(integer integer)
       (lambda (x y) (tag (+ x y))))
  (put 'sub '(integer integer)
       (lambda (x y) (tag (- x y))))
  (put 'mul '(integer integer)
       (lambda (x y) (tag (* x y))))
  (put 'div '(integer integer)
       (lambda (x y) (make-rational x y)))
  (put 'equ? '(integer integer) =)
  (put '=zero? '(integer)
       (lambda (x) (= 0 x)))
  (put 'make 'integer
       (lambda (x) (if (integer? x)
                       (tag x)
                       (error "non-integer value" x))))
  'done)

(define (make-integer n)
  ((get 'make 'integer) n))

;;;
;;; Real package
;;;
(define (install-real-package)
  (define (tag x)
    (attach-tag 'real x))    
  (put 'add '(real real)
       (lambda (x y) (tag (+ x y))))
  (put 'sub '(real real)
       (lambda (x y) (tag (- x y))))
  (put 'mul '(real real)
       (lambda (x y) (tag (* x y))))
  (put 'div '(real real)
       (lambda (x y) (tag (/ x y))))
  (put 'equ? '(real real) =)
  (put '=zero? '(real)
       (lambda (x) (= 0 x)))
  (put 'make 'real
       (lambda (x) (if (real? x)
                       (tag x)
                       (error "non-real value" x))))
  'done)

(define (make-real n)
  ((get 'make 'real) n))
While we're talking about type correctness, it's possibly also worth noting that we don't do anything to ensure that the numbers represented by our rational package conform to the definition of rational numbers. I.e. both the numerator and denominator must be integers in order for it to be a valid rational number. Nor do we do anything to enforce that a complex number's real and imaginary parts are real numbers.

Of course, depending upon your Scheme interpreter, or the implementation of gcd you're using, you might find that you're already prevented from creating rational representations with non-integer values. However, to be consistent with the integer and real packages we've created, and to ensure that type correctness is enforced regardless of interpreter, we'll also update the rational and complex packages to with the appropriate checks. In the case of the complex package we'll actually put the checks in the underlying rectangular and polar packages so that we're prevented from constructing invalid representations at as low a level as possible.

Here are the updates:
(define (install-rational-package)
  ;; internal procedures
  …
  (define (make-rat n d)
    (if (and (integer? n) (integer? d))
        (let ((g (gcd n d)))
          (cons (/ n g) (/ d g)))
        (error "non-integer numerator or denominator"
               (list n d))))
  …
  ;; interface to rest of the system
  …
  'done)


(define (install-rectangular-package)
  ;; internal procedures
  …
  (define (make-from-real-imag x y)
    (if (and (in-tower? x) (in-tower? y))
        (cons x y)
        (error "non-real real or imaginary value" (list x y))))
  …
  (define (make-from-mag-ang r a) 
    (if (and (real? r) (real? a))
        (cons (* r (cos a)) (* r (sin a)))
        (error "non-real magnitude or angle" (list r a))))
  …
  ;; interface to the rest of the system
  …
  'done)

(define (install-polar-package)
  ;; internal procedures
  …
  (define (make-from-mag-ang r a)
    (if (and (in-tower? r) (in-tower? a))
        (cons r a)
        (error "non-real magnitude or angle" (list r a))))
  …
  (define (make-from-real-imag x y) 
    (if (and (in-tower? x) (in-tower? y))
        (cons (sqrt (+ (square x) (square y)))
              (atan y x))
        (error "non-real real or imaginary value" (list x y))))
  …
  ;; interface to the rest of the system
  …
  'done)

Raising Types

Okay, so now onto the exercise itself. We need to design a procedure that will raise an object of a particular type one level in the tower. The section on Coercion gives the example coercion procedure scheme-number->complex. It seems logical that we want to introduce further coercion procedures that correspond to the steps in the type tower. Let's consider what each procedure should do:
  • integer->rational should convert an integer to a rational number by using the value of the integer as the numerator and, as 1 is the identity value for division, 1 as the denominator.
  • rational->real should convert a rational number to a real number by taking the numerator and denominator from the rational number and converting them to a single (real) number representing that rational number. Of course the simple way to achieve this is by dividing the numerator by the denominator.
  • real->complex should convert a real number to a complex number by using the value of the real number as the real component of the complex number and 0 as the imaginary component.
Here are the procedures:
(define (integer->rational i) (make-rational i 1))
(define (rational->real r) (make-real (/ (numer r) (denom r))))
(define (real->complex r) (make-complex-from-real-imag r 0))
Now what do we do with them?

We could simply install these procedures in the table under an appropriate key (such as raise) and then define a generic raise procedure that dispatches using apply-generic in the normal manner:
(define (raise x) (apply-generic 'raise x))
However, I feel that this approach has some issues:
  • It doesn't cope well with complex. We're not explicitly told the semantics for raise when dealing with complex representations. We're simply told that it should be an "operation that will work for each type (except complex)." If we implement raise using apply-generic then trying to raise a complex representation will result in an error. We could work around this by implementing and installing the identity transform procedure, complex->complex, but this doesn't quite feel right.
  • We're using coercion procedures, but we're not making any use of the get-coercion and put-coercion introduced in the section on Coercion.
  • The type tower is expressed implicitly by the procedures installed under the raise key. If we assume that each coercion procedure is defined and installed in the corresponding package (i.e. integer->rational is installed in the integer package, and so on) then this further means that there is no central location from which the type tower can be deduced and maintained.
To address these issues we can change our approach somewhat.

Let's install the coercion procedures using put-coercion and define the tower of types explicitly, as a list of types ordered from subtype to supertype (i.e. with integer first and complex last). raise can then simply find the type in the list, get the next type from its list as its immediate supertype and then get and use the appropriate coercion procedure to perform the raise. We've then got three special conditions to deal with and we can now deal with each separately:
  • If the type's not present in the list then we can raise an error indicating that we've been called with a type that's not in the tower of types. This may mean erroneous data, or it may mean that a new type has been introduced to the system that hasn't been properly incorporated into the tower of types yet.
  • If the type is found in the list and it has a supertype but there's no corresponding coercion procedure, then this indicates a programming error. We've added the type to the tower of types, but failed to add all the necessary coercion procedures to support the tower.
  • If the type is found in the list but it has no supertype then this indicates that the type is at the top of the tower of types. As noted before we're not told explicitly what to do with the top type. Let's just return the value unchanged as it's raised as high as it can be already.
Note also that nothing in this approach precludes us from installing other coercion procedures (e.g. such as integer->complex), so will still be possible for procedures to look for "shortcuts" in raising types, skipping intermediate types if an appropriate coercion procedure exists.

Okay, given all that, let's implement it:
(define tower-of-types '(integer rational real complex))

(define (raise x)
  (define (apply-raise types)
    (cond ((null? types)
           (error "Type not found in the tower-of-types"
                  (list x tower-of-types)))
          ((eq? (type-tag x) (car types))
           (if (null? (cdr types))
               x
               (let ((raiser (get-coercion (type-tag x) (cadr types))))
                 (if raiser
                     (raiser (contents x))
                     (error "No coercion procedure found for types"
                            (list (type-tag x) (cadr types)))))))
          (else (apply-raise (cdr types)))))
  (apply-raise tower-of-types))
And, for completion's sake, here's the changes to the types:
(define (install-integer-package)
  …
  (define (integer->rational i) (make-rational i 1))
  …
  (put-coercion 'integer 'rational integer->rational)
  …
  'done)

(define (install-rational-package)
  ;; internal procedures
  …
  (define (rational->real r) (make-real (/ (numer r) (denom r))))
  …
  ;; interface to rest of the system
  …
  (put-coercion 'rational 'real rational->real)
  …
  'done)

(define (install-real-package)
  …
  (define (real->complex r) (make-complex-from-real-imag r 0))
  …
  (put-coercion 'real 'complex real->complex)
  …
  'done)
Note that we don't need to make any changes to the complex package.

Let's see it in action:
> (raise (make-integer 2))
(rational 2 . 1)
> (raise (make-rational 3 4))
(real . 3/4)
> (raise (make-rational 5 3))
(real . 5/3)
> (raise (make-real 3.14159))
(complex rectangular 3.14159 . 0)
> (raise (make-real 1.234))
(complex rectangular 1.234 . 0)
> (raise (make-real 3/4))
(complex rectangular 3/4 . 0)

Addendum

2013-02-14 - identified as part of exercise 2.93 work!
Note that with the removal of support for the 'scheme-number primitive type we no longer need the tagging procedures attach-tag, type-tag and contents to cope with untagged types or with the 'scheme-number tag. As a result we can also revert these procedures to their pre-exercise 2.78 state:
(define (attach-tag type-tag contents)
  (cons type-tag contents))
(define (type-tag datum)
  (if (pair? datum)
      (car datum)
      (error "Bad tagged datum -- TYPE-TAG" datum)))
(define (contents datum)
  (if (pair? datum)
      (cdr datum)
      (error "Bad tagged datum -- CONTENTS" datum)))